Practice Problem Set 4 – Pareto Distribution

The previous post is a discussion of the Pareto distribution as well as a side-by-side comparison of the two types of Pareto distribution. This post has several practice problems to reinforce the concepts in the previous post.

Practice Problem 4A
The random variable X is an insurer’s annual hurricane-related loss. Suppose that the density function of X is:

    \displaystyle  f(x)=\left\{ \begin{array}{ll}                     \displaystyle  \frac{2.2 \ (250)^{2.2}}{x^{3.2}} &\ X > 250 \\           \text{ } & \text{ } \\           \displaystyle  0 &\ \text{otherwise}           \end{array} \right.

Calculate the inter-quartile range of annual hurricane-related loss.

Note that the inter-quartile range of a random variable is the difference between the first quartile (25th percentile) and the third quartile (75th percentile).

Practice Problem 4B
Claim size for an auto insurance coverage follows a Pareto Type II Lomax distribution with mean 7.5 and variance 243.75. Determine the probability that a randomly selected claim will be greater than 10.

Practice Problem 4C
Losses follow a Pareto Type II distribution with shape parameter \alpha>1 and scale parameter \theta. The value of the mean excess loss function at x=8 is 32. The value of the mean excess loss function at x=16 is 48. Determine the value of the mean excess loss function at x=32.

Practice Problem 4D

For a large portfolio of insurance policies, the underlying distribution for losses in the current year has a Pareto Type II distribution with shape parameter \alpha=2.9 and scale parameter \theta=12.5. All losses in the next year are expected to increases by 5%. For the losses in the next year, determine the value-at-risk at the security level 95%.

Practice Problem 4E (Continuation of 4D)

For a large portfolio of insurance policies, the underlying distribution for losses in the current year has a Pareto Type II distribution with shape parameter \alpha=2.9 and scale parameter \theta=12.5. All losses in the next year are expected to increases by 5%. For the losses in the next year, determine the tail-value-at-risk at the security level 95%.

Practice Problem 4F

For a large portfolio of insurance policies, losses follow a Pareto Type II distribution with shape parameter \alpha=3.5 and scale parameter \theta=5000. An insurance policy covers losses subject to an ordinary deductible of 500. Given that a loss has occurred, determine the average amount paid by the insurer.

Practice Problem 4G

The claim severity for an auto liability insurance coverage is modeled by a Pareto Type I distribution with shape parameter \alpha=2.5 and scale parameter \theta=1000. The insurance coverage pays up to a limit of 1200 per claim. Determine the expected insurance payment under this coverage for one claim.

Practice Problem 4H

For an auto insurance company, liability losses follow a Pareto Type I distribution. Let X be the random variable for these losses. Suppose that \text{VaR}_{0.90}(X)=3162.28 and \text{VaR}_{0.95}(X)=4472.14. Determine \text{VaR}_{0.99}(X).

Practice Problem 4I

For a property and casualty insurance company, losses follow a mixture of two Pareto Type II distributions with equal weights, with the first Pareto distribution having parameters \alpha=1 and \theta=500 and the second Pareto distribution having parameters \alpha=2 and \theta=500. Determine the value-at-risk at the security level of 95%.

Practice Problem 4J

The claim severity for a line of property liability insurance is modeled as a mixture of two Pareto Type II distributions with the first distribution having \alpha=1 and \theta=2500 and the second distribution having \alpha=2 and \theta=1250. These two distributions have equal weights. Determine the limited expected value of claim severity at claim size 1000.

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Problem Answer
4A 184.54
4B 0.20681035
4C 80
4D 23.7499
4E 43.1577
4F 1575.97
4G 1159.51615
4H 10,000
4I 4,958.04
4J 698.3681

\copyright 2017 – Dan Ma

2 thoughts on “Practice Problem Set 4 – Pareto Distribution

  1. Pingback: More on Pareto distribution | Applied Probability and Statistics

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